Understanding the Binomial Expansion of (x - y)³
The binomial theorem provides a systematic way to expand expressions of the form (x + y)ⁿ, where n is a non-negative integer. In this case, we'll focus on expanding (x - y)³, which is a special case of the binomial theorem.
The Binomial Theorem
The binomial theorem states that:
(x + y)ⁿ = ∑_(k=0)^n (n choose k) x^(n-k) y^k
where (n choose k) is the binomial coefficient, which represents the number of ways to choose k items from a set of n items. It's calculated as:
(n choose k) = n! / (k! * (n-k)!)
Expanding (x - y)³
Let's apply the binomial theorem to expand (x - y)³.
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Identify n: In this case, n = 3.
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Apply the formula:
(x - y)³ = ∑_(k=0)³ (3 choose k) x^(3-k) (-y)^k
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Expand the summation:
(x - y)³ = (3 choose 0) x³ (-y)⁰ + (3 choose 1) x² (-y)¹ + (3 choose 2) x¹ (-y)² + (3 choose 3) x⁰ (-y)³
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Calculate binomial coefficients:
- (3 choose 0) = 3! / (0! * 3!) = 1
- (3 choose 1) = 3! / (1! * 2!) = 3
- (3 choose 2) = 3! / (2! * 1!) = 3
- (3 choose 3) = 3! / (3! * 0!) = 1
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Substitute the values:
(x - y)³ = 1 * x³ * 1 + 3 * x² * (-y) + 3 * x * y² + 1 * 1 * (-y)³
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Simplify:
(x - y)³ = x³ - 3x²y + 3xy² - y³
Key Points
- The binomial theorem provides a systematic way to expand expressions with multiple terms raised to a power.
- The binomial coefficients can be calculated using the formula (n choose k) = n! / (k! * (n-k)!)
- When expanding (x - y)³, remember to include the negative sign in front of y and its powers.
By understanding the binomial theorem and its application to (x - y)³, you can expand similar expressions and gain valuable insights into their algebraic structure.